CEB Press v17.08 Calculations - Revision history

Marcin at 06:03, 1 July 2021

2021-07-01T06:03:16Z

← Older revision		Revision as of 06:03, 1 July 2021
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	*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm. Pump is .73 cu in - [https://www.surpluscenter.com/Hydraulics/Hydraulic-Pumps/Gear-Pumps/0-73-cu-in-Dynamic-GPF2012PC-Hydraulic-Pump-9-7790-B.axd]		*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm. Pump is .73 cu in - [https://www.surpluscenter.com/Hydraulics/Hydraulic-Pumps/Gear-Pumps/0-73-cu-in-Dynamic-GPF2012PC-Hydraulic-Pump-9-7790-B.axd]
	:We are using a 10.58 gpm pump. Formula is PSIGPM/1714 = 2500*10.58/1714 = 15.4 hp		:We are using a 10.58 gpm pump = 0.68". Formula is PSIGPM/1714 = 2500*10.58/1714 = 15.4 hp
	*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.		*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.
	:pir^216 = pi2.5^2*16= 314 cu in		:pir^216 = pi2.5^2*16= 314 cu in

Marcin at 22:54, 25 September 2017

2017-09-25T22:54:12Z

← Older revision		Revision as of 22:54, 25 September 2017
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	*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm. Pump is .73 cu in - [https://www.surpluscenter.com/Hydraulics/Hydraulic-Pumps/Gear-Pumps/0-73-cu-in-Dynamic-GPF2012PC-Hydraulic-Pump-9-7790-B.axd]		*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm. Pump is .73 cu in - [https://www.surpluscenter.com/Hydraulics/Hydraulic-Pumps/Gear-Pumps/0-73-cu-in-Dynamic-GPF2012PC-Hydraulic-Pump-9-7790-B.axd]
			:We are using a 10.58 gpm pump. Formula is PSIGPM/1714 = 2500*10.58/1714 = 15.4 hp
	*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.		*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.
	:pir^216 = pi2.5^2*16= 314 cu in		:pir^216 = pi2.5^2*16= 314 cu in

Marcin at 22:47, 25 September 2017

2017-09-25T22:47:34Z

← Older revision		Revision as of 22:47, 25 September 2017
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	*Pump of .73 cu in is 11.4 gpm theoretical, but specs say 10.58.		*Pump of .73 cu in is 11.4 gpm theoretical, but specs say 10.58.
	*10.6 gpm yield 6.1 bricks per minute!		*10.6 gpm yield 6.1 bricks per minute!
			:*10.6/1.74=6.1
	*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.0 block per minute! That's pretty blazing fast, at 8 seconds per block.		*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.0 block per minute! That's pretty blazing fast, at 8 seconds per block.

Marcin at 22:45, 25 September 2017

2017-09-25T22:45:45Z

← Older revision		Revision as of 22:45, 25 September 2017
Line 1:		Line 1:
	*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm.		*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm. Pump is .73 cu in - [https://www.surpluscenter.com/Hydraulics/Hydraulic-Pumps/Gear-Pumps/0-73-cu-in-Dynamic-GPF2012PC-Hydraulic-Pump-9-7790-B.axd]
	*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.		*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.
			:pir^216 = pi2.5^2*16= 314 cu in
			:pir^228 = pi1*28= 88 cu in
			:*Total = 402 cu in = 1.74 gallons
	*Pump of .73 cu in is 11.4 gpm theoretical, but specs say 10.58.		*Pump of .73 cu in is 11.4 gpm theoretical, but specs say 10.58.
	*10.6 gpm yield 6.1 bricks per minute!		*10.6 gpm yield 6.1 bricks per minute!
	*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.0 block per minute! That's pretty blazing fast, at 8 seconds per block.		*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.0 block per minute! That's pretty blazing fast, at 8 seconds per block.

Marcin at 02:06, 17 September 2017

2017-09-17T02:06:12Z

← Older revision		Revision as of 02:06, 17 September 2017
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	*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm.		*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm.
	*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.		*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.
	*Pump of .73 cu in is 11.4 gpm.		*Pump of .73 cu in is 11.4 gpm theoretical, but specs say 10.58.
	*11.4 gpm yield 6.6 bricks per minute!		*10.6 gpm yield 6.1 bricks per minute!
	*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.2 block per minute! That's pretty blazing fast, at 8 seconds per block.		*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.0 block per minute! That's pretty blazing fast, at 8 seconds per block.

Marcin at 01:27, 17 September 2017

2017-09-17T01:27:46Z

← Older revision		Revision as of 01:27, 17 September 2017
Line 1:		Line 1:
	According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm.		*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm.
			*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.
			*Pump of .73 cu in is 11.4 gpm.
			*11.4 gpm yield 6.6 bricks per minute!
			*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.2 block per minute! That's pretty blazing fast, at 8 seconds per block.

Marcin: Created page with "According to Hydraulic Calculations - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm."

2017-09-16T19:30:55Z

Created page with "According to Hydraulic Calculations - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm."

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According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm.