Hydraulic Cooler Sizing: Difference between revisions
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Heat dissipated = Horsepower * 0.3 * 2542 | Heat dissipated = Horsepower * 0.3 * 2542 | ||
Here are some | Here are some calculations for OSE engines: | ||
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|28 | |28 | ||
|28 * 0.25 * 2542 | |28 * 0.25 * 2542, 28 * 0.3 * 2542 | ||
|17794 - 21352 BTU/hr | |||
|21352 | |||
|- | |- | ||
|50 | |50 | ||
|50 * 0.3 * 2542 | |50 * 0.25 * 2542, 50 * 0.3 * 2542 | ||
|38130 BTU/hr | |31775 0 38130 BTU/hr | ||
|} | |} | ||
Revision as of 18:07, 28 April 2013
This page describes how to size a hydraulic oil cooler for a hydraulic system. Hydraulic coolers are often specified by their ability to dissipate heat - usually measured in BTU/hr.
1. The power in the hydraulic system:
Horsepower = Pressure * Flow / 1714
2. The heat dissipated in a hydraulic system can be determined by summing the inefficiencies of all components in the system, but is usually between 25% adn 30%. The heat dissipated is measured in BTU/hr:
Heat dissipated = Horsepower * 0.3 * 2542
Here are some calculations for OSE engines:
| Engine hp | Formula | Heat dissipated |
|---|---|---|
| 28 | 28 * 0.25 * 2542, 28 * 0.3 * 2542 | 17794 - 21352 BTU/hr |
| 50 | 50 * 0.25 * 2542, 50 * 0.3 * 2542 | 31775 0 38130 BTU/hr |
3. Select a cooler based on the BTU/hr derived in step 1 above. One resource for choosing a cooler is the following page from HaydenAuto.com - in the section "Heavy Duty Oil Coolers":
http://www.haydenauto.com/upload/HaydenAuto/Documents/Cat_Hayden/2007-hayden-trans-oil-coolers.pdf
For the case of the 50 hp Power Cube, select
Note: The "COOLING BTU / HR" ratings is with 2500 cubic-ft/min airflow and 100°F differential in oil and air temperatures. So, this requires a fan to move the air to meet these requirements.