Air Tool Efficiency: Difference between revisions
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*0.3kW for 7 atm CFM - [https://www.google.com/search?q=kw+to+cfm&oq=kw+to+cfm&aqs=chrome..69i57.9067j0j4&client=ubuntu&sourceid=chrome&ie=UTF-8] | *0.3kW for 7 atm CFM - [https://www.google.com/search?q=kw+to+cfm&oq=kw+to+cfm&aqs=chrome..69i57.9067j0j4&client=ubuntu&sourceid=chrome&ie=UTF-8] | ||
*Thus yes, if a tool needs 20 CFM at 7 atm - or 7 kW for its output. that is less than 10% efficient. | *Thus yes, if a tool needs 20 CFM at 7 atm - or 7 kW for its output. that is less than 10% efficient. | ||
=Links= | |||
*This post supports overall efficiency being about 5% - [http://www.wisedan.com/airloss.html] | |||
Revision as of 21:36, 1 April 2020
- 16kW to produce 100CFM at 100PSI - [1]
- 0.4 kW takes 20 CFM - [2]
- The above 2 numbers point to 3kW for 20 CFM - to get 0.4 kW out - or 13% efficiency of air tools. Extremely low.
More:
- 0.3kW for 7 atm CFM - [3]
- Thus yes, if a tool needs 20 CFM at 7 atm - or 7 kW for its output. that is less than 10% efficient.
Links
- This post supports overall efficiency being about 5% - [4]