Pile Driver Calculations: Difference between revisions

From Open Source Ecology
Jump to navigation Jump to search
No edit summary
 
(3 intermediate revisions by the same user not shown)
Line 1: Line 1:
=Basics=
=Basics=


*Need 45000 in lb or 170 kg m force
*Need 45000 in lb or 510 kg m force for basic helical pile driver
*Use a standard 5" sprocket with 3" hex shaf
*Use a standard 5" sprocket with 3" hex shaft - but 10x the meat in plastic.
*Sprockets can be CNC cut out of 1/2" steel at low cost
*Then belt is the only 'expensive' part for 1/2" 'meat' belt that is 5" wide.
*Calculations show 45000 in lb strength of such a belt, with 2x safety factor.


=More=
=More=
Line 9: Line 12:


[https://docs.google.com/presentation/d/1OSpEB7Ay0ycfBouK2Hs2xbtpJUj7juyv9Lx1eBb16Uc/edit#slide=id.g5c3be0ce2d_1_28 edit]
[https://docs.google.com/presentation/d/1OSpEB7Ay0ycfBouK2Hs2xbtpJUj7juyv9Lx1eBb16Uc/edit#slide=id.g5c3be0ce2d_1_28 edit]
=Files=
*[[File:5"sleeve.fcstd]]. [[File:5"sleeve.stl]]
**[[File:15"sleeve.fcstd]]. [[File:15"sleeve.stl]]
*[[File:5"belt.fcstd]]. [[File:5"belt.stl]]

Latest revision as of 22:17, 4 September 2020

Basics

  • Need 45000 in lb or 510 kg m force for basic helical pile driver
  • Use a standard 5" sprocket with 3" hex shaft - but 10x the meat in plastic.
  • Sprockets can be CNC cut out of 1/2" steel at low cost
  • Then belt is the only 'expensive' part for 1/2" 'meat' belt that is 5" wide.
  • Calculations show 45000 in lb strength of such a belt, with 2x safety factor.

More

edit

Files