CEB Press v17.08 Calculations: Difference between revisions

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According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm.
*According to [[Hydraulic Calculations]] - we need 17.5 hp to drive a 2500 PSI pump at 12 gpm. Pump is .73 cu in - [https://www.surpluscenter.com/Hydraulics/Hydraulic-Pumps/Gear-Pumps/0-73-cu-in-Dynamic-GPF2012PC-Hydraulic-Pump-9-7790-B.axd]
:*We are using a 10.58 gpm pump = 0.68". Formula is PSI*GPM/1714 = 2500*10.58/1714 = 15.4 hp
*One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.
:*pi*r^2*16 = pi*2.5^2*16= 314 cu in
:*pi*r^2*28 = pi*1*28= 88 cu in
:*Total = 402 cu in = 1.74 gallons
*Pump of .73 cu in is 11.4 gpm theoretical, but specs say 10.58.
*10.6 gpm yield 6.1 bricks per minute!
:*10.6/1.74=6.1
*Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.0 block per minute! That's pretty blazing fast, at 8 seconds per block.

Latest revision as of 06:03, 1 July 2021

  • We are using a 10.58 gpm pump = 0.68". Formula is PSI*GPM/1714 = 2500*10.58/1714 = 15.4 hp
  • One full 16" cycle of a 5" cylinder and a 28" cycle of a 2" cylinder yields 1.74 gallons per cycle if not counting rod volume.
  • pi*r^2*16 = pi*2.5^2*16= 314 cu in
  • pi*r^2*28 = pi*1*28= 88 cu in
  • Total = 402 cu in = 1.74 gallons
  • Pump of .73 cu in is 11.4 gpm theoretical, but specs say 10.58.
  • 10.6 gpm yield 6.1 bricks per minute!
  • 10.6/1.74=6.1
  • Rod volume is not negligible. From Cu in, subtract 39 cu in from 2.5" rod of large cylinder, and 11 cu in from small cylinder with 1" shaft. Subtract 50 cu in from total of 402 cu in - or 352 cu in. That is 1.52 gallons per cycle. That gets us 7.0 block per minute! That's pretty blazing fast, at 8 seconds per block.