Steam Calculations: Difference between revisions
		
		
		
		
		
		Jump to navigation
		Jump to search
		
				
		
		
	
|  (Added a Category to the Page) |  (Marked this Page for Later Work) | ||
| Line 1: | Line 1: | ||
| *3MJ/kg to evaporate water from room temp - https://www.quora.com/What-is-the-energy-needed-to-evaporate-1-kg-of-water. Or 0.8 kwhr. Or 3 kWhr/gallon. | *3MJ/kg to evaporate water from room temp - https://www.quora.com/What-is-the-energy-needed-to-evaporate-1-kg-of-water. Or 0.8 kwhr. Or 3 kWhr/gallon. | ||
| [[Category: Steam Engine]] | [[Category: Steam Engine]] [[Category: Incomplete Pages]] | ||
Latest revision as of 03:08, 29 January 2021
- 3MJ/kg to evaporate water from room temp - https://www.quora.com/What-is-the-energy-needed-to-evaporate-1-kg-of-water. Or 0.8 kwhr. Or 3 kWhr/gallon.