Steam Calculations: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
(Marked this Page for Later Work) |
||
(One intermediate revision by the same user not shown) | |||
Line 1: | Line 1: | ||
*3MJ/kg to evaporate water from room temp - https://www.quora.com/What-is-the-energy-needed-to-evaporate-1-kg-of-water. Or 0.8 kwhr. Or 3 kWhr/gallon. | *3MJ/kg to evaporate water from room temp - https://www.quora.com/What-is-the-energy-needed-to-evaporate-1-kg-of-water. Or 0.8 kwhr. Or 3 kWhr/gallon. | ||
[[Category: Steam Engine]] [[Category: Incomplete Pages]] |
Latest revision as of 03:08, 29 January 2021
- 3MJ/kg to evaporate water from room temp - https://www.quora.com/What-is-the-energy-needed-to-evaporate-1-kg-of-water. Or 0.8 kwhr. Or 3 kWhr/gallon.