Compressed Air Calculations: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
| Line 2: | Line 2: | ||
*Pressure - N/m2 - 3000 psi = 2E7 Pa. Delta V - of 1 liter or E-3 cu meter - to 214E-3 cu meter. | *Pressure - N/m2 - 3000 psi = 2E7 Pa. Delta V - of 1 liter or E-3 cu meter - to 214E-3 cu meter. | ||
*PdeltaV=2E7*214E-3=214E4=2E6 = 4MJ for that one expanded liter, as max possible work - but this is just PdeltaV without considering real thermodynamics underneath. Ballpart ok. | *PdeltaV=2E7*214E-3=214E4=2E6 = 4MJ for that one expanded liter, as max possible work - but this is just PdeltaV without considering real thermodynamics underneath. Ballpart ok. | ||
*Need to use PV-Work Calculator - | *Need to use PV-Work Calculator -https://www.geogebra.org/m/KAZHEN8c | ||
*See formula for energy density - [https://www.researchgate.net/figure/Energy-Density-of-Compressed-Air-in-Isothermal-Conditions-The-energy-density-is-a_fig1_225467912] | |||
https://www.geogebra.org/m/KAZHEN8c | |||
[[Category:calculators]] | [[Category:calculators]] | ||
Revision as of 14:32, 28 February 2021
- For example, compressed air at 2,900 psi (~197 atm) has an energy density of 0.1 MJ/L calculated from P*deltaV. [1]
- Pressure - N/m2 - 3000 psi = 2E7 Pa. Delta V - of 1 liter or E-3 cu meter - to 214E-3 cu meter.
- PdeltaV=2E7*214E-3=214E4=2E6 = 4MJ for that one expanded liter, as max possible work - but this is just PdeltaV without considering real thermodynamics underneath. Ballpart ok.
- Need to use PV-Work Calculator -https://www.geogebra.org/m/KAZHEN8c
- See formula for energy density - [2]