Worm Tower Calculations: Difference between revisions
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Feces is 75% water. [https://www.ncbi.nlm.nih.gov/pubmed/16802692]. It requires only 100 Whr to evaporate the water in feces. But, feces will be in a larger volume of water, such as 1 gallon - making it 0.6 kWhr for evaporation. Not bad. This would be an incinerating toilet. | Feces is 75% water. [https://www.ncbi.nlm.nih.gov/pubmed/16802692]. It requires only 100 Whr to evaporate the water in feces. But, feces will be in a larger volume of water, such as 1 gallon - making it 0.6 kWhr for evaporation. Not bad. This would be an incinerating toilet. | ||
For worms - | For worms - vermiposting works at approximately 1kg worm biomass per 1 kg feedstock per day - [https://www.sciencedirect.com/science/article/pii/S0960852499000553]. | ||
=Links= | =Links= | ||
*[[Open Source Separating Toilet]] | *[[Open Source Separating Toilet]] |
Revision as of 22:18, 4 April 2020
Problem Statement
Using Aquaponic Towers such as in the Aquaponic Greenhouse - how many of these towers - functioning as worm towers - would be required to process household blackwater?
Chemical Oxygen Demand per day per person is 100g - from Biodigester#Technical_Design_.2B_Calculations. About 1 lb wet feces per day.
Feces is 75% water. [1]. It requires only 100 Whr to evaporate the water in feces. But, feces will be in a larger volume of water, such as 1 gallon - making it 0.6 kWhr for evaporation. Not bad. This would be an incinerating toilet.
For worms - vermiposting works at approximately 1kg worm biomass per 1 kg feedstock per day - [2].